Home
Class 12
MATHS
A particle is projected horizontally fro...

A particle is projected horizontally from tower of height 79 m with speed `v_0` (in m/sec) . Due to air blow, it gets constant horizontal acceleration of `2m//s^2` in the direction of projection and it lands perpendicularly on inclined plane, then the value of `v_0` is ?

Text Solution

Verified by Experts

The correct Answer is:
15.40 to 15.70
Promotional Banner

Topper's Solved these Questions

  • TEST PAPER

    ALLEN |Exercise CHEMISTRY SECTION-I|20 Videos

  • TEST PAPER

    ALLEN |Exercise CHEMISTRY SECTION-II|16 Videos

  • TEST PAPER

    ALLEN |Exercise PHYSICS SECTION-I|20 Videos

  • SEQUENCE AND PROGRESSION

    ALLEN |Exercise Exercise (JA)|10 Videos

  • TEST PAPERS

    ALLEN |Exercise MATHEMATICS|136 Videos

Similar Questions

Explore conceptually related problems

A particle of mass 50 g is projected horizontally from the top of a tower of height 50 m with a velocity 20m//s . If g=10m//s^(2) , then find the :-

A particle is projected horizontally with speed u from the top of a plane inclined at an angle theta with the horizontal. How far from the point of projection will the particle strike the plane?

A particle is projected from a point O with an initial speed of 30 ms^(-1) to pass through a point which is 40 m from O horizontally and 10 m above O. There are two angles of projection for which this is possible. These angles are alpha and beta . The value of |tan (alpha+beta)| is

A particle is projected up the inclined such that its component of velocity along the incline is 10 m//s . Time of flight is 2 sec and maximum height above the incline is 5m . Then velocity of projection will be

A projectile is projected with some initial velocity and some initial angle of projection. A wind is also blowing, due to which constant horizontal retardation a is imparted to the particle in the plane of motion. It is found that, the particle is at same height at two different time t_(1) & t_(2) and particle is at same horizontal distance at two different time t_(3) & t_(4) Angle of projection of particle is :-

A particle is projected from a point P with a velocity v at an angle theta with horizontal. At a certain point Q it moves at right angles to its initial direction. Then

A particle is projected with a velocity v so that its range on a horizontal plane is twice the greatest height attained. If g is acceleration due to gravity, then its range is

A particle is dropped from the top of a tower. It covers 40 m in last 2s. Find the height of the tower.

If the container filled with liquid gets accelerated horizontally or vertically, pressure in liquid gets changed. In liquid ( a_(y) ) for calculation of pressure, effective g is used. A closed box horizontal base 6 m by 6 m and a height 2m is half filled with liquid. It is given a constant horizontal acceleration g//2 and vertical downward acceleration g//2 . Water pressure at the bottomof centre of the box is equal to (atmospheric pressure =10^(5)N//m^(2) density of water =1000 kg//m^(3),g=10m//s^(2) )

When a particle is undergoing motion, the diplacement of the particle has a magnitude that is equal to or smaller than the total distance travelled by the particle. In many cases the displacement of the particle may actually be zero, while the distance travelled by it is non-zero. Both these quantities, however depend on the frame of reference in which motion of the particle is being observed. Consider a particle which is projected in the earth's gravitational field, close to its surface, with a speed of 100sqrt(2) m//s , at an angle of 45^(@) with the horizontal in the eastward direction. Ignore air resistance and assume that the acceleration due to gravity is 10 m//s^(2) . " A third observer (C) close to the surface of the reports that particle is initially travelling at a speed of 100sqrt(2) m//s making on angle of 45^(@) with the horizontal, but its horizontal motion is northward". The third observer is moving in :-