Home
Class 12
MATHS
Two balls are projected simultaneously f...

Two balls are projected simultaneously from the top of a tall building. One vertically upward and other vertical downwards with same speed of 60 m/s.Then time interval between the balls striking the ground is :-

A

Ionic bond is present

B

The bond order of P-O bond is 1.25

C

All P-O bond length are same

D

Anionic part having tetrahedral unit

Text Solution

Verified by Experts

The correct Answer is:
A,C,D
Promotional Banner

Topper's Solved these Questions

  • TEST PAPER

    ALLEN |Exercise CHEMISTRY SECTION-II|16 Videos
  • TEST PAPER

    ALLEN |Exercise PHYSICS SECTION-II|16 Videos
  • SEQUENCE AND PROGRESSION

    ALLEN |Exercise Exercise (JA)|10 Videos
  • TEST PAPERS

    ALLEN |Exercise MATHEMATICS|136 Videos

Similar Questions

Explore conceptually related problems

Two particles P & Q are projected simultaneously from a point O on a level ground in the same vertical plane with the same speed in directions making angle of 30^(@) and 60^(@) respectively with the horizontal.

A ball is thrown vertically upwards. It was observed at a height h twice after a time interval Deltat . The initial velocity of the ball is

A ball is thrown downwards with a speed of 20 ms^(–1) from top of a building 150m high and simultaneously another ball is thrown vertically upwards with a speed of 30 ms^(–1) from the foot of the building. Find the time after which both the balls will meet - (g = 10 ms^(–2))

Two balls are thrown simultaneously, A vetically upwards with a speed of 20 ms^(-1) from the ground, and B vetically downwards from height of 40 m with the same speed and along the same line of motion. At what points do the two balls collide? Take g= 9.8 ms^(-2) .

Two particles of mass m_(1) and m_(2) are projected from the top of a tower. The particle m_(1) is projected vertically downward with speed u and m_(2) is projected horizontally with same speed. Find acceleration of CM of system of particles by neglecting the effect of air resistance.

A ball is projected vertically up wards with a velocity of 100 m/s. Find the speed of the ball at half the maximum height. (g=10 m//s^(2))

If a ball is thrown vertically upwards with a velocity of 40m//s , then velocity of the ball after 2s will be (g = 10m//s^(2))

A ball is dropped from a building of height 45 m. Simultaneously another ball is thrown up with a speed 40 m/s. Calculate the relative speed of the balls as a function of time.

A ball is thrown in vertically upward direction. It returns back to the same position in 2s. Then the maximum height achieved by the ball is ...... (Take g = 9.8 ms^(-2) )

A lift accelerates downwards from rest at rate of 2 m//s^(2) , starting 100 m above the ground. After 3 sec, an object falls out of the lift. Which will reach the ground first? What is the time interval between their striking the ground?