Velocity of a particle is given by v = (3t ^(2) +2t) m/s. Find its average velocity between t = 0 to t=3s and also find its acceleration at t = 3s. Motion of the particle is in one dimension.
The velocity of a particle is given by v=(2t^(2)-4t+3)m//s where t is time in seconds. Find its acceleration at t=2 second.
The velocity of a particle is given by v=(5t^(2)-2t+9)m//s where t is time in seconds. Find its acceleration at t=4 second.
The velocity of a particle is given by v=(4t^(2)-4t+5)m//s where t is time in seconds. Find its acceleration at t=4 second.
The velocity of a particle is given by v=(5t^(2)-6t+5)m//s where t is time in seconds. Find its acceleration at t=4 second.
The position of a particle moving on X-axis is given by x =At^(2) + Bt + C The numerical values of A, B and C are 7, -2 and 5 respectively and SI units are used. Find (a) The velocity of the particle at t= 5 (b) The acceleration of the particle at t =5 (c ) The average velocity during the interval t = 0 to t = 5 (d) The average acceleration during the interval t = 0 to t = 5
A particle moves in a straight line with a uniform acceleration a. Initial velocity of the particle is zero. Find the average velocity of the particle in first 's' distance.
The positon of an object moving along x-axis is given by x(t) = (4.2 t ^(2) + 2.6) m, then find the velocity of particle at t =0s and t =3s, then find the average velocity of particle at t =0 s to t =3s.
The displacement of a particle is given by x(t) = (4t ^(2) +8) meter. The instantaneous velocity of a particle at t = 2s is
The displacement of a particle is given by y (t) =2t ^(2) +5m. Hence its velocity at the end of 6 sec. will be ...... m/s.
