The vector sum of the forces of 10 newton and 6 newton can be:

Answer

`[c]=[L^(2)T^(-2)K^(-1)], [alpha]=[K^(-1)], [R]=[M^(1)L^(2)T^(-2)K^(-1) mol^(-1)]`

Explanation

(i)`c=Q/(m[T_2-T_1]`
Dimension of c`=[M^1L^2T^(-2))/([M^1L^0T^0][M^0L^0T^0K^1])`
`=[L^2T^(-2)K^(-1)]`
(ii)`alpha=(l_1-l_0)/(l_0(T_2-T_1))`
`implies` Dimension of `alpha=[M^0L^1T^(0))/([M^0L^1T^0][M^0L^0T^0K^1])`
(iii)`R=(PV)/(nT)=([M^1L^(-1)T^(-2)][L^3])/([mol][K])=[M^1L^2T^(-2)K^(-1)mol^(-1)]`