Home
Class 12
PHYSICS
The resultant of vecA and vecB is perpen...

The resultant of `vecA` and `vecB` is perpendicular to `vecA`. What is the angle between `vecA` and `vecB` ?

Text Solution

Verified by Experts

The correct Answer is:
1044
`vec(v)=(dvec(r))/(dt)=1.2 hat(i)+1.8that(j)-1.8t^(2)hat(k)`
at `t=4s, vec(v)=1.2 hat(i)+7.2 hat(j)-28.8 hat(k)`
`P=vec(F).vec(v)=(60hat(i)-25hat(j)-40hat(k)).(1.2hat(i)+7.2hat(j)-28.8hat(k))`
`=1044W`
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

Given that vecA=vecB . What is the angle between (vecA+vecB) and (vecA-vecB) ?

If vector (veca+ 2vecb) is perpendicular to vector (5veca-4vecb) , then find the angle between veca and vecb .

If veca and vecb are two unit vectors such that veca+2vecb and 5veca-4vecb are perpendicular to each other, then the angle between veca and vecb is

If vecA*vecB=AB , then angle between vecA and vecB will be …... .

The resultant of vecA and vecB makes an angle alpha with vecA and beta and vecB ,

The resultant of the vectors A and B is perpendicular to the vector A and its magnitude is equal to half the magnitude of vector B. The angle between vecA" and "vecB is :-

If |vecAxxvecB|=AB , then angle between vecA and vecB will be zero.

If vecA+ vecB = vecC and A+B=C , then the angle between vecA and vecB is :

What is the projection of vecA on vecB ?

if| vecAxxvecB|=|vecA.vecB| , then angle between vecA and vecB will be