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The magnitudes of vectors vecA,vecB and ...

The magnitudes of vectors `vecA,vecB` and `vecC` are respectively `12,5 and 13` unit and `vecA+vecB=vecC`, then the angle between `vecA` and `vecB` is :

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The correct Answer is:
C
`F=qvBrArr B=((MLT^(-2)))/([C][LT^(-1)])=MC^(-1)T^(-1)`
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