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The sum of magnitudes of two forces acti...

The sum of magnitudes of two forces acting at a point is `16 N`. If the resultant force is `8 N` and its direction is perpendicular to smaller force, then the forces are :-

A

6 N and 10N

B

8 N and 8 N

C

4 N and 12 N

D

2 N and 14 N

Text Solution

Verified by Experts

The correct Answer is:
B
`F=(1)/(4pi in_(0))(q_(1)q_(2))/r^(2)rArr [MLT^(-2)]=[1/in_(0)] (A^(2)T^(2))/L^(2)`
`rArr [epsilon_(0)]=[M^(-1)L^(-3)T^(4)A^(2)]`
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