If E is the electric field intensity `epsilon_(0)` is the permitivity of free space, then find dimensions of quantity `epsilon_(0) E^(2)`.

Options

A. The potential at all the points on the axis will be zero
B. The electric field at all the point on the axis will be zero
C. The direction of electric field at all points on the axis will be along the axis.
D. If the ring is placed inside a ubiform extermal electric field then net torque acting on the ring would be zero.

Answer

A

Explanation

Potential at any point is a scalequantity.
`:'` Position charge `=` negative charge i.e. the net charge is equal to zero. Hence potential is zero. Electric field is a vector quantity so it depends not only distance but also the way of distribution of charge.