Find the dimensional formula of surface energy.

Answer

D

Explanation

Potential at `C=(Kq)/(3a)-(Kq)/(4a)+(Kq')/(3a)=0rArr q'=-q/4`
Potential at `A=(Kq)/(2a)-(Kq)/(4a)-(Kq/4)/(3a)=(Kq)/(6a)`
Hence `V_(A)-V_(C)=(Kq)/(6a)`