Find the dimensional formula of angular acceleration.

Explanation

(a) Most accurate length of the cylinder will be the mean length `(vecl)`
`vecl=(3.29+3.28+3.29+3.31+3.28+3.27+3.29+3.30)/(8)=3.28875 cm "or" vecl=3.29cm`
(b) Absolute error in the first reading `=3.29-3.29=0.00cm`
Absolute error in the second reading =3.29-3.28=0.01cm
Absolute error in the thrid reading =2.29-3.29=0.00cm
Absolute error in the forth reading =3.39-3.31=-0.02cm
Absolute error in the fifith reading =3.29-3.28=0.01cm
Absolute error in the sixth reading =3.29-3.27=0.02cm
Absolute error in the seventh reading =3.29-3.29=0.00cm
Absolute error in the last reading =3.29-3.30=-0.01cm
(c) Mean absolute error `=vecDeltal=(0.00+0.01+0.00+0.02+0.01+0.02+0.00+0.01)/(8)=0.01 cm`
(d) Relative error in length `=(vecDeltal)/(l)=(0.01)/(3.29)=0.0030395=0.003`
(e) Percentage error `=(vecDeltal)/(vecl)xx100=0.003xx100=0.3%`
so length `l=3.29cm+-0.01cm` (in terms of absolute error)
or `t=3.29cm +- 0.30%` (in terms percentage error)