Write the dimensional formula of specific heat.

Explanation

(i) Area A=10Lxx10L=100`L^(2)`
percentage change in area `=(DeltaA)/(A)xx100=2xx(DeltaL)/(L)xx100=2xx=4%`
`(therefore(DeltaA)/(A)=(Delta100)/(100)+2(DeltaL)/(L)=0+2(DeltaL)/(L)=2(DeltaL)/(L))`
Note:- Constants do not have any error in them.
(ii) Volume `V=10Lxx10Lxx10L=1000 L^(3)`
percentage change in volume `=(DeltaV)/(V)xx100=3(DeltaL)/(L)=3xx2%=6%`