A vernier callipers has 20 divisions on the vernier scale which coincide with 19 divisions on the main scale. The least count of the instrument is 0.1 mm. The main scale divisions are of
Text Solution
Verified by Experts
The correct Answer is:
B
Positive charge has a tendency to move from higher potential to lower potential hence it will move from `B (-20 V)` to `A(-30V)`.
|
Topper's Solved these Questions
BASIC MATHS
ALLEN |Exercise Comprehension 7|3 Videos
BASIC MATHS
ALLEN |Exercise Comprehension 8|4 Videos
BASIC MATHS
ALLEN |Exercise Exercise-05|1 Videos
AIIMS 2019
ALLEN |Exercise PHYSICS|39 Videos
CIRCULAR MOTION
ALLEN |Exercise EXERCISE (J-A)|6 Videos
Similar Questions
Explore conceptually related problems
In a vernier calliper, N divisions of vernier scale coincide with (N-1) divisions of main scale (in which division represent 1mm). The least count of the instrument in cm. should be
In a vernier calliper, N divisions of vernier scale coincide with (N-1) divisions of main scale (in which division represent 1mm). The least count of the instrument in cm. should be
In a vernier callipers, one main scale division is x cm and n divisions of the vernier scale coincide with (n-1) divisions of the main scale. The least count (in cm) of the callipers is :-
Consider a Vernier callipers in which each 1cm on the main scale is divided into 8 equal divisions and a screw gauge with 100 divisions in its circular scale. In the Vernier callipers, 5 divisions of the Vernier scale coincide with 4 divisions on the scale and in the screw gauge, one complete rotation of the circular scale moves it by two divisions on the linear scale. Then :
One centimetre on the main scale of vernier callipers is divided into ten equal parts. If 10 divisions of vernier scale coincide with 8 small divisions of the main scale, the least count of the callipers is
In a vernier callipers, N divisions of the main scale coincide with N + m divisions of the vernier scale. what is the value of m for which the instrument has minimum least count.
The edge of a cube is measured using a vernier callipers. [ 9 divisions of the main scale is equal to 10 divisions of the vernier scale and 1 main scale dividsion is 1 mm ]. The main scale division reading is 10 and 1st division of vernier scale was found to be coinciding with the main scale. The mass of the cube is 2.736 g . Calculate the density in g//cm^3 upto correct significant figures.
On cm on the main scale of vernier callipers is divided into ten equal parts. If 20 division of vernier scale coincide with 8 small divisions of the main scale. What will be the least count of callipers ?
In a given slide callipers 10 division of its vernier coincides with its 9 main scale divisions. If one main scale division is equal to 0.5 mm then find its least count.
The main scale of a vernier callipers reads in millimeter and its vernier is divided into 10 divisions which coincides with 9 divisions of the main scale. The reading for shown situation is found to be (x//10) mm. Find the value of x. .
