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A particle starts motion from rest and m...

A particle starts motion from rest and moves along a straight line. Its acceleration-time graph is shown. Find out speed of particle at t=2s and at t=3s.

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The correct Answer is:
7
In time of gight i.e. `7` s, the vertical displacement of A is zero and that of B is 49 m so relative motion of B w.r.t. a `(u_(2)sin theta_(2)-u_(1)sintheta_(1))xx7=49rArr u_(2)sin theta_(2)-u_(1)sin theta_(1)=7 m//s`
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Knowledge Check

  • A particle, starting from rest, moves with constant acceleration 4 ms^(-2). The distance travelled by the particle in 5^(th) second is.

    A
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    B
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    C
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    D
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