In a straight line motion the distance travelled is proportional to the square root of the time taken The acceleration of the particle is proportional to :-

Answer

D

Explanation

`x=10sqrt(3)t, y=10t-t^(2), (dx)/(dt)=10sqrt(3)`
`v_(y)=(dy)/(dt)=10-2trArr at t=5`sec
`v_(y)` becomes zero at maximum height
`rArr y=10xx5-5^(2)=25 m`.