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A man walks on a straight road form his home to a market 2.5 km away with speed of 5 `(km)/(hr)`. Finding the market closed, he instantly turns and walks back home with a speed of 7.5 `(km)/(hr)`. The average speed of the man over the intervel of time 0 to 40 min is equal to

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The correct Answer is:
A, D
As air drag reduces the vertical component of velocity so time to reach maximum height will decrease and it will decrease the downward vertical velocity hence time to fall on earth increases.
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ALLEN -MOTION IN A PALNE-EXERCISE-02
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  2. A ball is thrown upwards . Its height varies with time as shown in fig...

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  3. A man walks on a straight road form his home to a market 2.5 km away w...

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  4. A particle experiences a constant acceleration for 20 sec after starti...

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  5. If a ball is thrown vertically upwards with speed u, the distance cove...

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  6. A man throws balls with the same speed vertically upwards one after th...

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  8. The velocity of a particle is given by v=(5t^(2)-6t+5)m//s where t is ...

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  9. Which of the following equation represents the motion of a body moving...

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  10. The variation of velocity of a particle moving along a straight line i...

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  11. Find the integration of the 1/(2x+1).

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  12. The numerical ratio of displacement to the distance covered is always

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  13. Which of the following velocity-time graphs shows a realistic situatio...

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  14. A particle moves in straight line in same direction for 20 seconds wit...

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  15. A body starts from rest and moves with a uniform acceleration of 10ms^...

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  16. An object travels 10km at a speed of 100 m/s and another 10km at 50 m/...

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  17. A body starting from rest moves along a straight line with a constant ...

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  18. Acceleration-time graph of a body is shown. The corresponding velocity...

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  19. Velocity-time curve for a body projected vertically upwards is with ti...

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