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An elevator is accelerating upward at a ...

An elevator is accelerating upward at a rate of `6ft(sec^(2)` when a bolt from its celling falls to the floor of the lift (Distance=9.5feet). The time taken (in seconds) by the falling bolt to hit the floor is (take `g=32ft//sec^(2)`)

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The correct Answer is:
(A)-p, (B)-v, (C)-s, (D)-q, (E)-u, (F)-t, (G)-r
Slope of v.t. curve gives acceleration (instantaneous) at that point `vec(a)=(dvec(v))/(dt)`
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