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A particle moving along x-axis has accel...

A particle moving along x-axis has acceleration `f`, at time `t`, given by `f = f_0 (1 - (t)/(T))`, where `f_0` and `T` are constant.
The particle at `t = 0` has zero velocity. In the time interval between `t = 0` and the instant when `f = 0`, the particle's velocity `(v_x)` is :

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The correct Answer is:
B
To meet, co-ordinates must be same. So in frame of one particle, second particle should approach it.
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