A particle has an initial velocity (6hati+8hatj) ms^(-1) and an acceleration of (0.8hati+0.6hatj)ms^(-2) . Its speed after 10s is
A particle has an initial velocity (12hati+10hatj) ms^(-1) and an acceleration of (0.5hati+0.6hatj)ms^(-2) . Its speed after 20s is
A particle has initial velocity (5hati+7hatj) and acceleration (0.7hati+0.5hatj) . The magnitude of velocity after 10 second will be
A particle has velocity (6t^3hati+8t^2hatj) ms^(-1) find the velocity of the particle
A cricket ball of mass 150 g has an initial velocity mu=(3hati+4hatj) ms^(-1) and a final velocity v = - (3hat(i) + 4hat(j)) ms^(-1) , after being hit. The change in momentum (final momentuminitial momentum) is (in kgms^(-1) )
A projectile is given an initial velocity hati+2 hatj .The cartesin equation of its path is (g=10ms^(-2))
In a reference frame a man A is moving with velocity (3hati-4hatj)ms^(-1) and another man B is moving with velocity (hati+hatj)ms^(-1) relative to A. Find the actual velocity of B.
A projectile is thrown with an initial velocity of (a hati +b hatj) ms^(-1) . If the range of the projectile is twice the maximum height reached by it, then
A particle is projected from ground with initial velocity 3hati + 4hatj m/s. Find range of the projectile :-
Motion of Mass Center in Vector Form A 2.0 kg particle has a velocity of vecv_1=(2.0hati-3.0hatj) m /s, and a 3.0 kg particle has a velocity vecv_2=(1.0hati+6.0hatj) m/s. (a) How fast is the center of mass of the particle system moving? (b) Find velocities of both the particles in centroidal frame.
