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A man runs at a speed of 4m//s to overta...

A man runs at a speed of `4m//s` to overtake a standing bus. When he is `6m` beind the door at `t=0`, the bus mover forward and continuous with a constant acceleration of `1.2m//s^(2)`. The man reaches the door in time `t`. Then

A

`4t=6+0.6t^2`

B

`4t=0.6t^2`

C

`t=0.6t^2`

D

`4t=1.2+0.6t^2`

Text Solution

Verified by Experts

The correct Answer is:
A

Range of A `=(u^(2) sin2theta)/g=(10xxsin 120^(@))/10=sqrt(3)/2`
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