A ball dropped from the top of a tower covers a distance `7x` in the last second of its journey, where `x` is the distance covered in the first second. How much time does it take to reach to ground?.

Answer

`-3hat(k) rad//s^(2), -2hat(k) rad//s`

Explanation

`vec(a_(1))=6hat(i)=vec(alpha)xxvec(R)=vec(alpha)xx2hat(j)rArr vec(alpha)=-3hat(k) rad//s^(2)`
`vec(a_(r))=-8hat(j)=vec(omega)xxvec(v)=vec(omega)xx(omegaR)hat(i) rArr vec(omega)=-2hat(k) rad//s`