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A body X is projected upwards with a vel...

A body X is projected upwards with a velocity of `98 ms^(-1)`, after 4s, a second body Y is also projected upwards with the same initial velocity . Two bodies will meet after

Text Solution

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The correct Answer is:
`((v_(1)+v_(2))^(2))/(2(a_(1)+a_(2)))`
`v_(12) = v_(1) - v_(2) = v_(1) - (-v_(2))=v_(1) + v_(2)`

`a_(12) = -a_(1) - a_(2) = -(a_(1) + a_(2))`.
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