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A man standing on a road has to hold his...

A man standing on a road has to hold his umbrella at `30^(@)` with the vertical to keep the rain away. He throws the umbrella and starts running at 10km/hr. He finds that rain drop are hitting his head vertically. Find the speed of rain drops with respect to (a) road (b) the moving man.

Text Solution

Verified by Experts

The correct Answer is:
`2/(sqrt(2)+1)`

For stone : `2h=((u sin theta)^(2))/(2g)` & `h=(u sin theta)t-1/2 g t^(2)`
`rArr t=(sqrt(40h)+-sqrt(20h))/(10)rArr Deltat=sqrt(0.8h)=2/10 sqrt(20 h)`

Horizontal displacement : `vt_(2)=u cos theta Deltat`
`rArr (v(sqrt(2)+1)sqrt(20h))/10=u cos thetaxx(2sqrt(20h))/10`
`rArr v/(u cos theta)=(2)/(sqrt(2)+1)`
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