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A stone is dropped from the top of a tow...

A stone is dropped from the top of a tower of height `h`. Aftre `1 s` another stone is droppped from the balcony `20 m` below the top. Both reach the bottom simultaneously. What is the value of `h` ? Take `g=10 ms^(-2)`.

Text Solution

Verified by Experts

The correct Answer is:
5

With respect to train:
Time of flight : `T=(2v_(y))/g=(2xx5sqrt(3))/10=sqrt(3)`
By using `s=ut+1/2 at^(2)`
we have `1.15=5T-1/2 aT^(@)rArr a=5 m//s^(2)`
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Knowledge Check

  • A stone is dropped from the top of tower. If its velocity at the mid point of height of tower is 10ms^(-1), then the height of a tower is ..... (g = 10 ms^(-2))

    A
    10
    B
    16
    C
    8
    D
    20
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