A stone is dropped from the top of a tower of height `h`. Aftre `1 s` another stone is droppped from the balcony `20 m` below the top. Both reach the bottom simultaneously. What is the value of `h` ? Take `g=10 ms^(-2)`.
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The correct Answer is:
5
With respect to train: Time of flight : `T=(2v_(y))/g=(2xx5sqrt(3))/10=sqrt(3)` By using `s=ut+1/2 at^(2)` we have `1.15=5T-1/2 aT^(@)rArr a=5 m//s^(2)`
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