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A particle is moing with a velocity of 1...

A particle is moing with a velocity of `10m//s` towards east. After 10s its velocity changes to `10m//s` towards north. Its average acceleration is:-

A

zero

B

`sqrt(2) m//s^(2)` towards N-W

C

`(2)/sqrt(2) m//s^(2)` towards N-W

D

`(1)/sqrt(2)m//s^(2)` towards N-W

Text Solution

Verified by Experts

The correct Answer is:
B
Acceleration `veca=(Deltavecv)/(Deltat)=(10hatj-10hati)/(10)`
`=-hati+hatj` (west north)
`|veca|=sqrt(1+1)=sqrt(2)` (north-west)
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