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Two particles are projected from the two...

Two particles are projected from the two towers simultaneously, as shown in the figure.

What should be value of `d` for their collision.

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There is no relative acceleration of B w.r.t. A.
So time of collision `t=(y_(BA))/((v_(y))_(BA))` Whre `y_(BA)=` vertical displacement of B w.r.t A=10m. `&`
`v_(yBA)=` vertical velocity of B w.r.t. `A=0-(-10sqrt(2)sin 45^(@))=10m//srArrt=(10)/(10)=1s`
`d=` horizontal distance travelled by B w.r.t. A=`(V)(x)_(BA)xxt=(10+10sqrt(2) cos 45^(@))xx1=20m`.
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