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A particle of mass m is projected with v...

A particle of mass m is projected with velocity making an angle of `45^(@)` with the horizontal When the particle lands on the level ground the magnitude of the change in its momentum will be .

A

`mvsqrt(2)`

B

zero

C

2 mv

D

`mv//sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`|overlineDeltaoverlineP|=2mv sin theta`
`=2xx mvxxsin4%^(@)`
`=sqrt(2)mv`
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