Home
Class 12
PHYSICS
A particle is projected with a velocity ...

A particle is projected with a velocity u making an angle `theta` with the horizontal. At any instant its velocity becomes v which is perpendicular to the initial velocity u. Then v is

A

`u cos theta`

B

`u tan theta`

C

`u cot theta`

D

`u sec theta`

Text Solution

Verified by Experts

The correct Answer is:
C


`because` horizontal component of velocity remains same
`therefore u cos theta=v cos (90-theta)`
`u cos theta=v sin theta rArr v=ucot theta`
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PALNE

    ALLEN |Exercise EXERCISE-3|41 Videos
  • MOTION IN A PALNE

    ALLEN |Exercise SOLVED EXAMPLE|28 Videos
  • MOTION IN A PALNE

    ALLEN |Exercise EXERCISE-1|99 Videos
  • KINEMATICS-2D

    ALLEN |Exercise Exercise (O-2)|47 Videos
  • NEWTON'S LAWS OF MOTION & FRICTION

    ALLEN |Exercise EXERCISE (JA)|4 Videos

Similar Questions

Explore conceptually related problems

A particle is fired with velocity u making angle theta with the horizontal.What is the change in velocity when it is at the highest point?

A particle is projected from a point P with a velocity v at an angle theta with horizontal. At a certain point Q it moves at right angles to its initial direction. Then

A particle is projected with a speed v and an angle theta to the horizontal. After a time t, the magnitude of the instantaneous velocity is equal to the magnitude of the average velocity from 0 to t. Find t.

A particle is projected with a velocity 10 m/s at an angle 37^(@) to the horizontal. Find the location at which the particle is at a height 1 m from point of projection.

A particle is projected upwards with a velocity of 100 m//s at an angle of 60^(@) with the vertical. Find the time when the particle will move perpendicular to its initial direction, taking g = 10 m//s^(2) .

A body of mass m is projected with intial speed u at an angle theta with the horizontal. The change in momentum of body after time t is :-

A particle A is projected with speed v_(A) from a point making an angle 60^(@) with the horizontal. At the same instant, a second particle B is thrown vertically upwards from a point directly below the maximum hieght point of parabolic path of A with velocity v_(B) . If the two particles collide then the ratio of v_(A)//v_(B) should be

A particle of mass m is projected with speed u at an angle theta with the horizontal. Find the torque of the weight of the particle about the point of projection when the particle is at the highest point.

Match the following In groung to ground projection a particle is projected at 53^(@) from horizontal. At t=25 sec after projection, its velocity vector becomes perpendicular to its initial velocity vector. ("Given "vec(a)=g darr= 10 m//s^(2))

A particle of mass m is projected with velocity making an angle of 45^(@) with the horizontal When the particle lands on the level ground the magnitude of the change in its momentum will be .

ALLEN -MOTION IN A PALNE-EXERCISE-2
  1. A cannon of mass 5m (including a shell of mass m) is at rest on a smoo...

    Text Solution

    |

  2. The range of a projectile when fired at 75^(@) with the horizontal is ...

    Text Solution

    |

  3. A particle is projected with a velocity u making an angle theta with t...

    Text Solution

    |

  4. The speed at the maximum height of a projectile is sqrt(3)/(2) times o...

    Text Solution

    |

  5. What is the ratio of P.E. w.r.t. ground and K.E. at the top most point...

    Text Solution

    |

  6. A ball is thrown at an angle theta with the horizontal and the range i...

    Text Solution

    |

  7. A student is able to throw a ball vertically to maximum height of 40m....

    Text Solution

    |

  8. Three projectile A, B and C are thrwon from the same point in the same...

    Text Solution

    |

  9. A projectile is thrown with an initial velocity of (a hati +b hatj) ms...

    Text Solution

    |

  10. The equation of a projectile is y=sqrt(3)x-(gx^(2))/(2) the angle of...

    Text Solution

    |

  11. The equation of projectile is y=16x-(x^(2))/(4) the horizontal range i...

    Text Solution

    |

  12. If a projectile is fired at an angle theta with the vertical with velo...

    Text Solution

    |

  13. If R is the maximum horizontal range of a particle, then the greatest ...

    Text Solution

    |

  14. Two stones are projected with the same speed but making different angl...

    Text Solution

    |

  15. A projectile is thrown from a point in a horizontal plane such that th...

    Text Solution

    |

  16. A particle is projected with a velocity v so that its range on a horiz...

    Text Solution

    |

  17. A projectile is thrwon into space so as to have the maximum possible h...

    Text Solution

    |

  18. A particle is fired with velocity u making angle theta with the horizo...

    Text Solution

    |

  19. A missile is fired for maximum range with an initial velocity of 40m//...

    Text Solution

    |

  20. An arrow is shot into air. Its range is 200m and its time of flight is...

    Text Solution

    |