Home
Class 12
PHYSICS
The equation of projectile is y=16x-(x^(...

The equation of projectile is `y=16x-(x^(2))/(4)` the horizontal range is:-

A

16m

B

8m

C

64m

D

12.8m

Text Solution

Verified by Experts

The correct Answer is:
C
`y=16x-(x^(2))/(y)`
`y=16x(1-(x)/(64))`
Comparing with `y=x tan theta(1-(x)/(R))`
R=64m
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PALNE

    ALLEN |Exercise EXERCISE-3|41 Videos

  • MOTION IN A PALNE

    ALLEN |Exercise SOLVED EXAMPLE|28 Videos

  • MOTION IN A PALNE

    ALLEN |Exercise EXERCISE-1|99 Videos

  • KINEMATICS-2D

    ALLEN |Exercise Exercise (O-2)|47 Videos

  • NEWTON'S LAWS OF MOTION & FRICTION

    ALLEN |Exercise EXERCISE (JA)|4 Videos

Similar Questions

Explore conceptually related problems

The equation of projectile is y = 16 x - (5)/(4)x^(2) find the horizontal range

The equation of a projectile is y=sqrt(3)x-(gx^(2))/(2) the angle of projection is:-

A particle is projected in x-y plane with y- axis along vertical, the point of projection being origin. The equation of projectile is y = sqrt(3) x - (gx^(2))/(2) . The angle of projectile is ……………..and initial velocity is ………………… .

The velocity of projection of oblique projectile is (6hati+8hatj)ms^(-1) The horizontal range of the projectile is

The horizontal range of a projectile is R and the maximum height attained by it is H. A strong wind now begins to below in the direction of motion of the projectile, giving it a constant horizontal acceleration =g//2 . Under the same conditions of projection. Find the horizontal range of the projectile.

The range of a projectile when fired at 75^(@) with the horizontal is 0.5km. What will be its range when fired at 45^(@) with same speed:-

The range of a projectile launched at an angle of 15^(@) with horizontal is 1.5km. The range of projectile when launched at an angle of 45^(@) to the horizontal is

The angle of projection at which the horizontal range and maximum height of projectile are equal is

In case of a projectile fired at an angle equally inclined to the horizontal and vertical with velocity (u). The horizontal range is:-

Assertion: In projectile motion, when horizontal range is n times the maximum height, the angle of projection is given by tan theta=(4)/(n) Reason: In the case of horizontal projection the vertical increases with time.

ALLEN -MOTION IN A PALNE-EXERCISE-2
  1. A projectile is thrown with an initial velocity of (a hati +b hatj) ms...

    Text Solution

    |

  2. The equation of a projectile is y=sqrt(3)x-(gx^(2))/(2) the angle of...

    Text Solution

    |

  3. The equation of projectile is y=16x-(x^(2))/(4) the horizontal range i...

    Text Solution

    |

  4. If a projectile is fired at an angle theta with the vertical with velo...

    Text Solution

    |

  5. If R is the maximum horizontal range of a particle, then the greatest ...

    Text Solution

    |

  6. Two stones are projected with the same speed but making different angl...

    Text Solution

    |

  7. A projectile is thrown from a point in a horizontal plane such that th...

    Text Solution

    |

  8. A particle is projected with a velocity v so that its range on a horiz...

    Text Solution

    |

  9. A projectile is thrwon into space so as to have the maximum possible h...

    Text Solution

    |

  10. A particle is fired with velocity u making angle theta with the horizo...

    Text Solution

    |

  11. A missile is fired for maximum range with an initial velocity of 40m//...

    Text Solution

    |

  12. An arrow is shot into air. Its range is 200m and its time of flight is...

    Text Solution

    |

  13. In the Q.23, the maximum height attained by the arrow is:-

    Text Solution

    |

  14. In the Q.23, the vertical component of the velocity is:-

    Text Solution

    |

  15. what is the angle? when sin (theta)=4 and cos (theta)=5

    Text Solution

    |

  16. The ceiling of a hall is 40m high. For maximum horizontal distance, th...

    Text Solution

    |

  17. a body is thrown horizontally with a velocity sqrt(2gh) from the top o...

    Text Solution

    |

  18. When a particle is thrown horizontally, the resultant velocity of the ...

    Text Solution

    |

  19. A ball is projected upwards from the top of a tower with a velocity 50...

    Text Solution

    |

  20. A ball is thrown at different angles with the same speed u and from th...

    Text Solution

    |