The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. The number of electrons stricking the target per second is ...... (Take `e=1.6xx10^(-19)C)`

Explanation

Velocity of the mass center `vec(v)_(c ) = (m_("jeep")vec(v)_("jeep") + m_("car")vec(v)_("car"))/(m_("jeep") + m_("car"))`
Assuming direction of motion in the positive x-direction, we have
`vecv_c=(m_(jeep)vecv_(jeep)+m_(car)vecv_(car))/(m_(jeep)+m_(car))" "vecv_c=(2400xx80+1600xx60)/(2400+1600)=(72km)`
(b) Velocity of the jeep in centroidal frame `v_((jeep)//c)=80-72=8km/h` in positive x-direction.
Velocity of the car in centroidal frame `V_(car//c)=60-72=-(12km)/h`
`(12km)/h` negative x-direction direction.