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In the circuit shown here, E(1) = E(2) =...

In the circuit shown here, `E_(1) = E_(2) = E_(3) = 2 V` and `R_(1) = R_(2) = 4 ohms`. The current flowing between point `A` and `B` through battery `E_(2)` is

A

0

B

`1.875`

C

`2.5`

D

`1.25`

Text Solution

Verified by Experts

The correct Answer is:
C
`v = u + at rArr 5 = 15 - (4) t rArr t = 2.5 sec`
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