Three resistance of values `2Omega,3Omega` and ` 6Omega` are to be connected to produce an effective resistance of `4Omega`. This can be done by connecting.

Answer

A

Explanation

`x_(cm) = (m_(1)x_(1) + m_(2)x_(2))/(2m) rArr x_(1) + x_(2) = (f)/(2m) t^(2)`
`x_(1) - x_(2) = x_(0)`
Therefore `x_(1) = (f)/(4m) -t^(2) + (x_(0))/(2)`
From above equations `x_(2) = (ft^(2))/(4m) - (x_(0))/(2)`