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There is a current of 40 ampere in a wir...

There is a current of 40 ampere in a wire of `10^(-6)m^(2)` are of cross-section. If the number of free electron per `m^(3)` is `10^(29)` then the drift velocity will be

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Verified by Experts

The correct Answer is:
A

Thrust `= F = rhoAv^(2) " " [A = pir^(2)]`
at equilibrium `rhoAv^(2) = mg`
Power `P = Fv = rhoAv^(3)`
`= (mg)/(r ) sqrt((mg)/(p pi))`
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