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A copper wire has a square cross-section...

A copper wire has a square cross-section, 2.0 mm on a side. It carries a current of 8 A and the density of free electrons is `8 xx 10^(28)m^(-3)`. The drift speed of electrons is equal to

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Verified by Experts

The correct Answer is:
`(mg(h_(3) - h_(1)))/((h_(2) - h_(1)))`
From work energy theoem
`W_(F) + W_(g) = DeltaKE`
`F_(avg) (h_(2) - h_(1)) - mg(h_(3) - h_(1)) = 0 rArr F_(avg) = (mg(h_(2) - h_(1)))/((h_(2) - h_(1)))`
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ALLEN -CURRENT ELECTRICITY-EXERCISE-IV A
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