The current in conductor varies with time `t` as `I = 2 t + 3 t^(2)` where `I` is in ampere and `t` in seconds. Electric charge flowing through a section of the conductor during `t = 2 sec` to `t = 3 sec` is

Answer

`(4g)/(9), (13mg)/(18)`

Explanation

`mg - T = m (a - (g)/(6))` …(i)
`rArr T - (m)/(2)g = (m)/(2)a` …(ii)
For solving eq. (i) & (ii)
`a = (4g)/(9)` & `T = (13)/(18)mg`