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The equivalent resistance and potential ...

The equivalent resistance and potential difference between A and B for the circuit is respectively

Text Solution

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The correct Answer is:
`((m_(2) + m_(1) cot alpha) h)/(m + m_(1) + m_(2))`
`Deltax_(cm) = 0 = (mx_(0) + m_(1) (x_(0) - h cot alpha) + m_(2) (x_(0) - h))/(m + m_(1) + m_(2))`
`rArr x_(0) = ( (m_(2) + m_(1) cot alpha))/((m + m_(1) + m_(2)))`
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