An unknown resistance `R_(1)` is connected is series with a resistance of `10 Omega`. This combination is connected to one gap of a meter bridge, while other gap is connected to another resistance `R_(2)`. The balance point is at `50 cm` Now , when the `10 Omega` resistance is removed, the balanced point shifts to `40 cm` Then the value of `R_(1)` is.

Answer

`e = 0.8, mu = 0.4`

Explanation

`u_(s) = sqrt(2g(1 - cos 60^(@))) = sqrt(2g xx (1)/(2)) = 3.13 m//s`
`COLM rArr 5u_(B) = 4 xx u_(s) rArr u_(B) = (4)/(5) sqrtg = 2.53 m//s`
Energy equation `(1)/(2)m ((4)/(5) sqrtg)^(2) = mu mg xx 0.8 rArr mu = 0.4`
`e = -((v_(2) - v_(1))/(u_(2) - u_(1))) = 0.8`