A thermocouple of negligible resistance produces an emf fo `40 mu V//^(@)C` in the linear range of temperature. A galvanometer of resistance `10 Omega` whose sensitivity is `1 mu A//div` is employed with the thermocouple. The smallest value of temperature difference that can be detected by the system will

Answer

`4 m//s`

Explanation

For collision between A & B
`v_(A) = ((m - 2m))/((m + 2m)) (9) = -3 ms^(-1)`
`v_(B) = (2(m))/((m + 2m))(9) = +6ms^(-1)`
For collision between B and C
`v_(c ) = ((2m)/(2m + m)) (6) = 4ms^(-1)`