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In the circuit shown the resistance of v...

In the circuit shown the resistance of voltmeter is `10000 ohm` and that of ammeter is `20 ohm`. The ammeter reading is `0.10 amp` and voltmeter reading is 12 volts. Then `R` is equal to

A

`122Omega`

B

`100Omega`

C

`118Omega`

D

`116Omega`

Text Solution

Verified by Experts

The correct Answer is:
2
`V=I(R+R_(A))rArr12=0.1(R+20)`
`rArrR=(12)/( 0.1)-20 R=100Omega`
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ALLEN -CURRENT ELECTRICITY-EX.II
  1. In the following circuit the reading of the voltmeter will be:-

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  2. In the following diagram the deflection in the galvanometer in a poten...

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  3. In the circuit shown the resistance of voltmeter is 10000 ohm and that...

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  4. Value of Current i in the following circuit is:-

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  5. The resistance of galvanometer is G ohm and the range is 1 volt. The v...

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  6. The total resistance between x and y in ohm is:-

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  7. In an experiment to measure the internal resistance of a cell by a pot...

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  8. There are n similar conductors each of resistance R . The resultant re...

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  9. A galvanometer of resistance 100Omega gives full scale deflection for ...

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  10. If only 2% of the main current is to be passed through a galvanometer ...

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  11. In the following circuit diagram the value of resistance X for the pot...

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  12. The sensitivity of a potentiometer is increased by

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  13. A potential gradient is created in the wire by a standard cell for the...

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  14. A voltmeter having a resistance of 998 ohms is connected to a cell of ...

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  15. Find the potential difference between X and Y in volt is:-

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  16. A cell of e.m.f. 2V and negligible internal resistance is connected to...

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  17. Potentiometer wire length is 10m, having a total resistance of 10Omega...

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  18. P,Q is a uniform wire of resistance 2000Omega and m the md point PQ. A...

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  19. A student connects a voltmeters, ammeter and resistance according to t...

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  20. A potentiometer wire has length 4 m and resistance 8Omega. The resista...

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