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Power dissipated across the 8 Omega in t...

Power dissipated across the `8 Omega` in the circuit shown here is `2 W`. The power dissiated in watt units across the `3 Omega` is

A

`2.0`

B

`1.0`

C

`0.5`

D

`3.0`

Text Solution

Verified by Experts

As voltage drop across `8Omega=sqrt(2xx8)`
`=4V(because P=(V^(2))/(R))`
Therefore voltage drop across `3Omega=3V`
[`because 4V` is divided in ratio of resistances between `1Omega` and `3Omega`]
Hence power dissipated in `3Omega=((3)^(2))/(3)=3` watt
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