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The vertical height y and horizontal dis...

The vertical height y and horizontal distance x of a projectile on a certain planet are given by `x= (3t) m, y= (4t-6t^(2))` m where t is in seconds, Find the speed of projection (in m/s).

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Knowledge Check

  • The displacement of a particle is given by x = (t-2)^(2) where x is in metre and t in second. The distance covered by the particle in first 4 seconds is

    A
    4m
    B
    8m
    C
    12m
    D
    16m

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