ABCD is a trapezium such that AB and CD ...

ABCD is a trapezium such that `AB and CD` are parallel and `BC _|_ CD`. If `/_ADB= theta `, BC =p and CD=q`, then AB is equal to

A

`(p^2+q^2)/(p^2cos theta+q^2sintheta)`

B

`((p^2+q^2)sin theta)/(pcos theta+qsintheta)^2`

C

`((p^2+q^2)sin theta)/(pcos theta+qsintheta)`

D

`(p^2+q^2sin theta)/(pcos theta+qsintheta)`

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The correct Answer is:

C

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