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C0+C1+C2+.........+C(N-1)+CN=...

`C_0+C_1+C_2+.........+C_(N-1)+C_N=`

A

`2^(n-1)`

B

`""^(2n C_n)`

C

`2^(n)`

D

`2^(n+1)`

Text Solution

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The correct Answer is:
C
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