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If vecA= 2hati+nhatj-1hatk and vecB=1hat...

If `vecA= 2hati+nhatj-1hatk and vecB=1hati+2hatj+3hatk`, then findt the value of n so that `vecA bot vecB`.

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Dot product of two mutually parpendicular vectors is zero `vecA*vecB =0`
`therefore (4hati+nhatj-2hatk)*(2hati+3hatj+hatk)=0 rArr (4xx2)+ (nxx3) + (-2xx1)=0 rArr 3n =-6 rArr n =-2`
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