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Frequency f of a simple pendulum depends...

Frequency f of a simple pendulum depends on its length l and acceleration g due to gravity according to the following equation `f=1/(2pi)sqrt(g/l)`
Graph between which of the following quantities is a straight line?

A

f on the ordinate and `l` on the abscissa

B

f on the ordinate and `sqrtl` on the abscissa

C

`f^(2)` on the ordinate and `l` on the abscissa

D

`f^(2)` on the ordinate and `1//l` on the abscissa

Text Solution

Verified by Experts

The correct Answer is:
D
`because f= (1)/(2pi)sqrt((g)/(l))" " therefore f^(2) prop (1)/(l)`
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