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Given that P=Q=R. if vecP+vecQ=vecR then...

Given that `P=Q=R`. if `vecP+vecQ=vecR` then the angle between `vecP & vecR` is `theta_(1)` and `vecP+vecQ+vecR=0` then the angle between `vecP & vecR` is `theta_(2)`. What is the relation between `theta_(1)` and `theta_(2)`.

A

`theta_1 = theta_2`

B

`theta_1 = (theta_2)/(2)`

C

`theta_1= 2theta_2`

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
2
`vec(Delta r) = vec(OB) - vec(OA)`
`|vec(OA)| = |vec(OB)| =l `
`|vec(Deltar)| = sqrt(l^(2) + l^(2) -2l^(2) cos theta )`
`= sqrt(2l^(2) (1-costheta) ) = sqrt(2l^(2) xx 2sin^(2)theta//2)` ltBrgt `= 2l sin theta//2`
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