The length, breadth and thickness of a metal sheet are `4.234 m,1.005m` and 2.01 cm respectively. Give the area and volume of the sheet to correct number of significant figures.

Explanation

length `(l)` = 4.234 m
breadth (b) = 1.005 m
thickness (t) `= 2.01 cm = 2.01 xx 10^(-2) ` m
Therefore area of the sheet `= 2(l xx b+ b xx t + t xxl)`
`" "= 2 ( 4.234 xx 1.005 + 1.005 xx 0.0201 + 4.234) m^(2)`
`" "= 2(4. 3604739) m^(2) = 8.720978 m^(2)`
Since area can contain a maximum of 3 SF therefore, rounding off, we get : Area = `8.72 m^(2)`
Likewise volume `=l xx b xx t = 4.234 xx 1.005 xx 0.0201 m^(3) = 0.0855289 m^(3)`
Since volume can contain 3 SF, therefore after rounding off, we get: Volume = 0.0855 `m^(3)`