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If x, y, z are in arithmetic progression...

If x, y, z are in arithmetic progression and a is the arithmetic mean of x and y and b is the arithmetic mean of y and z, then prove that y is the arithmetic mean of a and b.

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The correct Answer is:
C

`x=a+b = 14 pm 0.14 rArr % `error `= (0.14)/(14) xx 100 = 1% , y = a-b= 2 pm 0.14 rArr % ` error `= (0.14)/(2) xx 100 = 7% `
`z= ab = 48 pm 0.96 rArr %` error `= (0.96)/(48) xx 100 = 2% `. Therefore order of % error is `x lt z lt y`
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