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Taking foce, length and time to be the f...

Taking foce, length and time to be the fundamental quantities find the dimension of
a. density, b. pressure,
c. momentum and d. energy

Text Solution

Verified by Experts

The correct Answer is:
(a) `[M^(0)L^(0)T^(0)K^(1)]`
(b) `[ML^(2) T^(-2)]`
(c ) `[ML^(-1)T^(-2)]`
(d) `[M^(0)L^(0)T^(-1)]`
(a) [Temperature] = [K]
(b) KE = `(1)/(2) mv^(2)`
`rArr [KE] = [m] [v]^(2) = M(LT^(-1))^(2) = [ML^(2)T^(-2]`
(c ) P `= (F)/(A) rArr [P] = ([F]) /( [A]) = (MLT^(-2)) /(L^(2)) = [ML^(-1)T^(-2)]`
(d) `omega = (v)/(r ) rArr [omega] = ([v]) /([r]) = (LT^(-1))/(L) = [T^(-1)]`
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