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The external and internal radius of a ho...

The external and internal radius of a hollow cylinder are measured to be `(4.23+-0.01)cm` and `(3.89+-0.01)cm`. The thickness of the wall of the cylinder is :-

A

`(0.34 pm 0.02)` cm

B

`(0.17 pm 0.02)` cm

C

`(0.17 pm 0.01)` cm

D

`(0.34 pm 0.01)` cm

Text Solution

Verified by Experts

The correct Answer is:
A
Thickness of cylinder can be written as
`t = t pm Delta t`
`t= r_2 - r_1 = 4.23 - 3.89 = 0.34`
`Delta t = Delta r_1 + Delta r_2 = 0.01 + 0.01 = 0.02`
` t (0.34 pm 0.02)` cm
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