Home
Class 11
PHYSICS
One centimetre on the main scale of vern...

One centimetre on the main scale of vernier callipers is divided into ten equal parts. If 10 divisions of vernier scale coincide with 8 small divisions of the main scale, the least count of the callipers is

A

0.01 cm

B

0.02 cm

C

0.05 cm

D

0.005 cm

Text Solution

Verified by Experts

The correct Answer is:
B
L.C = `((b-a)/(b))M= ((10-8)/(10))xx (1)/(10)` cm = 0.02 cm
Promotional Banner

Topper's Solved these Questions

  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN |Exercise EXERCISE-II AIPMT 2006|1 Videos

  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN |Exercise EXERCISE-II AIIMS 2006|1 Videos

  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN |Exercise EXERCISE-I ERRORS|18 Videos

  • MISCELLANEOUS

    ALLEN |Exercise Question|1 Videos

  • SEMICONDUCTORS

    ALLEN |Exercise Part-3(Exercise-4)|50 Videos

Similar Questions

Explore conceptually related problems

On cm on the main scale of vernier callipers is divided into ten equal parts. If 20 division of vernier scale coincide with 8 small divisions of the main scale. What will be the least count of callipers ?

In a vernier callipers, one main scale division is x cm and n divisions of the vernier scale coincide with (n-1) divisions of the main scale. The least count (in cm) of the callipers is :-

A vernier callipers has 20 divisions on the vernier scale which coincide with 19 divisions on the main scale. The least count of the instrument is 0.1 mm. The main scale divisions are of

The diameter of a cylinder is measured using a vernier callipers with no zero error . It is found that the zero of the vernier scale lies between 5.10 and 5.15 cm of the main scale .the vernier scale has 50 division equivalent to 2.45 cm . The 24 th division of the vernier scale exactly coincides with one of the main scale divisions . The diameter of the cylinder is

In a vernier calliper, N divisions of vernier scale coincide with (N-1) divisions of main scale (in which division represent 1mm). The least count of the instrument in cm. should be

In a vernier calliper, N divisions of vernier scale coincide with (N-1) divisions of main scale (in which division represent 1mm). The least count of the instrument in cm. should be

In a vernier callipers, n divisions of its main scale match with (n+1) divisions on its vernier scale. Each division of the main scale is a units. Using the vernier principle, calculate its least count.

The vernier of a circular scale is divided into 30 divisons, which coincides with 29 main scale divisions. If each main scale division is (1//2)^@ the least count of the instrument is (1^@=60')

in an experiment the angles are required to be using an instrument, 29 divisions of the main scale exactly coincide with the 30 divisions of the vernier scale. If the sallest division of the main scale is half- a degree (= 0.5^(@) , then the least count of the instrument is :

The main scale of a vernier callipers reads in millimeter and its vernier is divided into 10 divisions which coincides with 9 divisions of the main scale. The reading for shown situation is found to be (x//10) mm. Find the value of x. .